(renderer) rename vars, add comments
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@ -434,7 +434,7 @@ function TreeBuilder:tree() return self.nodes end
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--- @param x `T`[]
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--- @param x `T`[]
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--- @param y T[]
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--- @param y T[]
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--- @param cost? { of_delete?: fun(x: T): number; of_add?: fun(x: T): number; of_change?: fun(x: T, y: T): number; }
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--- @param cost? { of_delete?: fun(x: T): number; of_add?: fun(x: T): number; of_change?: fun(x: T, y: T): number; }
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--- @return LevenshteinChange<T>[]
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--- @return LevenshteinChange<T>[] The changes, from last (greatest index) to first (smallest index).
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function H.levenshtein(x, y, cost)
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function H.levenshtein(x, y, cost)
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-- At the moment, this whole `cost` plumbing is not used. Deletes have the
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-- At the moment, this whole `cost` plumbing is not used. Deletes have the
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-- same cost as Adds or Changes. I can imagine a future, however, where
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-- same cost as Adds or Changes. I can imagine a future, however, where
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@ -474,10 +474,10 @@ function H.levenshtein(x, y, cost)
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if x[i] == y[j] then
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if x[i] == y[j] then
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dp[i][j] = dp[i - 1][j - 1] -- no cost if items are the same
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dp[i][j] = dp[i - 1][j - 1] -- no cost if items are the same
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else
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else
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local costDelete = dp[i - 1][j] + cost_of_delete_f(x[i])
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local cost_delete = dp[i - 1][j] + cost_of_delete_f(x[i])
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local costAdd = dp[i][j - 1] + cost_of_add_f(y[j])
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local cost_add = dp[i][j - 1] + cost_of_add_f(y[j])
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local costChange = dp[i - 1][j - 1] + cost_of_change_f(x[i], y[j])
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local cost_change = dp[i - 1][j - 1] + cost_of_change_f(x[i], y[j])
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dp[i][j] = math.min(costDelete, costAdd, costChange)
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dp[i][j] = math.min(cost_delete, cost_add, cost_change)
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end
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end
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end
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end
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end
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end
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